Add part 2 (digit1 detection works)

day-1/example-input

@@ -0,0 +1,7 @@
+two1nine
+eightwothree
+abcone2threexyz
+xtwone3four
+4nineeightseven2
+zoneight234
+7pqrstsixteen

day-1/input

@@ -998,3 +998,4 @@ one269
 29onecklhjcxvpbzfour3
 35vksqxhbnxk
 sixfdqttpskdnbksqxg9three6bqqpngfhz
+yriferiufjuifirtjhgrifjearifjesix

day-1/part-2/part-2.py

@@ -0,0 +1,60 @@
+#!/usr/bin/env python3
+DEBUG = False
+
+num_text = ['zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine']
+#num_text = {0: 'zero', 1: 'one', 2: 'two', 3: 'three', 4: 'four', 5: 'five', 6: 'six', 7: 'seven', 8: 'eight', 9: 'nine'}
+
+with open('day-1/input', 'rt') as f:
+    numbers = []
+    for line in f:
+        # just removes the newline to make printing work a bit better
+        line = line.rstrip()
+        digit1 = -1
+        
+        # go through each line, start at the beginning, and keep going until it either matches a digit or it spelled out
+        # can probably be made more efficient
+        for i in range(0, len(line)):
+            if line[i].isdigit():
+                digit1 = int(line[i])
+            else:
+                # spelled out detection
+                for num in num_text:
+                    # to make sure it doesn't go over the end
+                    # fancy if thing needed so it doesn't go way over the end
+                    end = i + len(num) if i + len(num) < len(line) else len(line)
+                    
+                    if line[i:end] in num_text:
+                        digit1 = num_text.index(line[i:end])
+                    if digit1 != -1:
+                        break
+            if digit1 != -1:
+                break
+        
+        if DEBUG:
+            print('digit 1 debug:', line, digit1)
+        
+        # TODO: digit 2, basically the same thing in reverse
+        digit2 = -1
+
+
+
+
+        '''
+        for char in line:
+            if str.isdigit(char):
+                digit1 = char
+                break
+
+        for i in range(len(line) - 2, -1, -1):
+            if str.isdigit(line[i]):
+                digit2 = line[i]
+                break
+        '''
+
+        # append if nums found, otherwise print error
+        numbers.append(int(str(digit1) + str(digit2))) if digit1 != -1 and digit2 != -1 else print(line, 'failed:', digit1, digit2, end='\n\n')
+
+total = 0
+for num in numbers:
+    total += num
+print(total)

day-1/part-2/readme.md

@@ -0,0 +1,17 @@
+# Day 1 - Part 2
+
+Your calculation isn't quite right. It looks like some of the digits are actually **spelled out with letters**: one, two, three, four, five, six, seven, eight, and nine also count as valid "digits".
+
+Equipped with this new information, you now need to find the real first and last digit on each line. For example:
+
+```txt
+two1nine
+eightwothree
+abcone2threexyz
+xtwone3four
+4nineeightseven2
+zoneight234
+7pqrstsixteen
+```
+
+In this example, the calibration values are `29`, `83`, `13`, `24`, `42`, `14`, and `76`. Adding these together produces 281.